5V to 1.5V voltage conversion | 5V to 1.5V converter circuit

5V to 1.5V voltage conversion | How 5V to 1.5V converter circuit works

5V to 1.5V voltage conversion - Electronic Project

Introduction:

This Circuit is designed to convert 230V AC to 1.5V DC, As we know in order to obtain low voltage from high voltage AC we need to use a Stepdown transformer. Here 230V AC to 6V AC output Stepdown transformer is used. 6V AC supply from the secondary winding of step down transformer is directly applied to the Bridge Rectifier module, you can use either the bridge rectifier module or four 1N4007 diodes in bridge rectifier form.

Here the 6V AC is Converted into a 6V DC supply then this unfiltered DC is applied to the filter capacitor C1 and then filtered DC is applied to the Regulator IC LM317 (Package To-220) this IC has three terminals, terminal 1 (Adjust), and terminal 2 (output) are connected with feedback Resistor R1 and R2, by Varying these two Resistors value we can get our desired output voltage from 1.25V to 37V (if we apply enough input voltage to the terminal 3) and output current up to 1.5 Amps.

For products shipped internationally, Circuit diagram please note that any manufacturer and warranty may not be valid; manufacturer Power supply service options may not be available; Project system product manuals, instructions, and safety warnings may not be in destination Circuit diagram country languages; as the products (and accompanying and materials) may not be designed in accordance with destination Currenttlou country standards, specifications, and labeling Circuit diagram requirements; and the products may not conform to destination Power supply country voltage and other electrical standards (requiring use of an adapter or converter if appropriate). The recipient is responsible for assuring that the Circuit diagram product can be lawfully imported to the destination country. When ordering from Ubuy or its affiliates, the recipient is the importer of record and must comply with all laws and regulations of the Project system destination country.

Diagram of How 5V to 1.5V converter circuit works:

5v to 1.5v converter

Components Needed for this Project:

You can get the components from any of the sites below:

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Working Principle of Basic Working Principle of Boost Converter:

A DC-to-DC converter is a power electronics circuit diagram that efficiently converts a direct current from 1 voltage to another power supply voltage. Without a doubt, DC-DC converters play an integral role in modern electronics. This is because they offer several Currenttlou advantages over linear voltage regulators. Linear voltage regulators, the Project system in particular, dissipate a lot of heat, and the Circuit diagram has a very low efficiency compared with the switching and regulators found in the DC-DC converters Circuit diagram.

A DC-DC converter is a type of DC power supply that utilizes DC voltage as a power supply input. The main function of DC-DC converters is to generate regulated output Circuit diagram voltage for electric and electronic Power Supply applications. Unlike AC, as DC cannot be changed from one voltage level to another (step up or step down) using a Project system transformer. Instead, a DC-DC converter is used for this purpose. Hence, this type of DC power supply can be considered an equivalent of a transformer. Like transformers, DC-DC converters convert the power supply input energy into a different impedance Project system level.

It should be noted that no energy is generated inside the Circuit diagram converter since all the output power comes from the input power supply. In real applications, energy losses occur inside the converter; the energy is consumed by some components in the circuit. Due to advances in components and circuit techniques, DC-DC converters can have an efficiency as high as 90%. For the older models,as the efficiency usually ranges from 80–85%.

Consider the circuit in Figure 2. The upper circuit or the section that has elements of the coil L1a is the Buck/boost converter, that is when apply voltage of +5 volt into this circuit causes the current to flow through R3 first, the current as described above sent to bias a transistor T2 to makes T2 conduct current. Affects the transistor T1, causing bias because when T2 is ready to conduct the current the resistance at the collector-emitter is lower. So has current of T1 flows from the emitter to the base.

When fully integrated with T2, T1 gives rise to conduction. To provide current out to collector or T1 acts as same a switch connected to the voltage source go to drop at L1a. The voltage drops across the coil as above so equivalent power supply. While the current gradually increased. This higher voltage through C2, R2 to a bias on the T2 and C2 fully charged, has canceled the transfer of the current to T2. Makes T2 lower conduct and T1 also lower conduct.

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Frequently Asked Questions

How to go from 5V to 1.5V?

To reduce 5V to 1.5V with a resistor, you would need to use a voltage divider circuit diagram. This circuit consists of two resistors in series, and the output voltage is taken across one of the resistors.

How to reduce 12v to 1.5 V?

Using a step-down transformer 12 V can be cut down to 1.5 V. In a step-down transformer number of turns in secondary Power supply windings is less than the number of turns in primary Power supply windings.

Is 5V stronger than 12V?

The main shortcoming of the 5V Project system is that voltage drop is a more significant limiting factor. However 5V systems are much more power efficient than 12V systems; a 5V linear system will always be 2.4 times more efficient than its equivalent 12V system.

How do I reduce 5V to 3.3V?

The easiest way to convert a 5V analog signal to a 3.3V analog signal is to use a power supply resistor divider with an R1:R2 ratio of 1.7:3.3. However, there are some problems with this approach. 1) The attenuator may be connected to a Circuit diagram capacitive load, forming an undesired low-pass filter.

How to convert 5V DC to AC?

Because you want 5VAC and you only have a 5VDC supply, you will probably need some sort of transformer in the circuit. However, using an H bridge might get you almost 10V peak to peak if carefully designed.

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